Aubbeenaubbee Township, Fulton County, Indiana
Township in Indiana, United States / From Wikipedia, the free encyclopedia
Aubbeenaubbee Township[pronunciation?] is one of eight townships in Fulton County, Indiana. As of the 2020 census, its population was 1,346 (down from 1,448 at 2010[4]) and it contained 624 housing units.
Quick Facts Country, State ...
Aubbeenaubbee Township | |
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Coordinates: 41°09′00″N 86°25′00″W | |
Country | United States |
State | Indiana |
County | Fulton |
Government | |
• Type | Indiana township |
Area | |
• Total | 34.69 sq mi (89.8 km2) |
• Land | 34.49 sq mi (89.3 km2) |
• Water | 0.2 sq mi (0.5 km2) |
Elevation | 741 ft (226 m) |
Population | |
• Total | 1,346 |
• Density | 42/sq mi (16/km2) |
FIPS code | 18-02656[3] |
GNIS feature ID | 453053 |
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