Jefferson Township, Sullivan County, Indiana
Township in Indiana, United States / From Wikipedia, the free encyclopedia
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Jefferson Township is one of nine townships in Sullivan County, Indiana, United States. At the 2020 census, its population was 355 and it contained 218 housing units.[1]
More information Census, Pop. ...
Census | Pop. | Note | %± |
---|---|---|---|
1890 | 1,837 | — | |
1900 | 1,953 | 6.3% | |
1910 | 2,199 | 12.6% | |
1920 | 2,177 | −1.0% | |
1930 | 1,758 | −19.2% | |
1940 | 1,903 | 8.2% | |
1950 | 1,400 | −26.4% | |
1960 | 1,051 | −24.9% | |
1970 | 800 | −23.9% | |
1980 | 887 | 10.9% | |
1990 | 544 | −38.7% | |
2000 | 495 | −9.0% | |
2010 | 417 | −15.8% | |
2020 | 355 | −14.9% | |
Source: US Decennial Census[2] |
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Quick Facts Country, State ...
Jefferson Township | |
---|---|
Coordinates: 38°57′43″N 87°17′19″W | |
Country | United States |
State | Indiana |
County | Sullivan |
Government | |
• Type | Indiana township |
Area | |
• Total | 42.95 sq mi (111.2 km2) |
• Land | 42.42 sq mi (109.9 km2) |
• Water | 0.53 sq mi (1.4 km2) 1.23% |
Elevation | 623 ft (190 m) |
Population (2020) | |
• Total | 355 |
• Density | 8.3/sq mi (3.2/km2) |
ZIP codes | 47528, 47838, 47848, 47882 |
GNIS feature ID | 453498 |
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