Mahopac, New York
Census-designated place & hamlet in New York, United States / From Wikipedia, the free encyclopedia
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Mahopac (/ˈmeɪəˌpæk/ or /ˌməˈhoʊpæk/) is a hamlet (and census-designated place) in the town of Carmel in Putnam County, New York, United States. Also known as Lake Mahopac, the exurb is located some 47 miles (76 km) north of New York City, on US Route 6 at the county's southern central border with Westchester County. As of the 2020 census, the population was 8,933.[2]
Quick Facts Country, State ...
Mahopac, New York | |
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Coordinates: 41°22′11″N 73°44′15″W | |
Country | United States |
State | New York |
County | Putnam |
Town | Carmel |
Area | |
• Total | 7.32 sq mi (18.96 km2) |
• Land | 6.13 sq mi (15.87 km2) |
• Water | 1.19 sq mi (3.09 km2) |
Elevation | 666 ft (203 m) |
Population (2020) | |
• Total | 8,932 |
• Density | 1,457.33/sq mi (562.72/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 10541 |
Area code | 845 |
FIPS code | 36-44534 |
GNIS feature ID | 0956273 |
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