Sand Creek Township, Decatur County, Indiana
Township in Indiana, United States / From Wikipedia, the free encyclopedia
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Sand Creek Township is one of nine townships in Decatur County, Indiana, United States. As of the 2020 census, its population was 3,122 (slightly up from 3,120 at 2010[3]) and it contained 1,331 housing units.[4]
More information Census, Pop. ...
Census | Pop. | Note | %± |
---|---|---|---|
1890 | 2,499 | — | |
1900 | 2,562 | 2.5% | |
1910 | 2,370 | −7.5% | |
1920 | 2,146 | −9.5% | |
1930 | 1,861 | −13.3% | |
1940 | 2,034 | 9.3% | |
1950 | 2,002 | −1.6% | |
1960 | 2,378 | 18.8% | |
1970 | 2,769 | 16.4% | |
1980 | 3,206 | 15.8% | |
1990 | 3,040 | −5.2% | |
2000 | 3,061 | 0.7% | |
2010 | 3,120 | 1.9% | |
2020 | 3,122 | 0.1% | |
Source: US Decennial Census[5] |
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Quick Facts Country, State ...
Sand Creek Township | |
---|---|
Coordinates: 39°12′24″N 85°33′11″W | |
Country | United States |
State | Indiana |
County | Decatur |
Government | |
• Type | Indiana township |
Area | |
• Total | 43.21 sq mi (111.9 km2) |
• Land | 43.17 sq mi (111.8 km2) |
• Water | 0.04 sq mi (0.1 km2) |
Elevation | 856 ft (261 m) |
Population (2020) | |
• Total | 3,122 |
• Density | 72/sq mi (28/km2) |
FIPS code | 18-67734[2] |
GNIS feature ID | 453832 |
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