Searsburg, Vermont
Town in Vermont, United States / From Wikipedia, the free encyclopedia
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Searsburg is a town in Bennington County, Vermont, United States. The population was 126 at the 2020 census.[3]
Quick Facts Country, State ...
Searsburg, Vermont | |
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Coordinates: 42°53′22″N 72°57′48″W | |
Country | United States |
State | Vermont |
County | Bennington |
Area | |
• Total | 21.6 sq mi (55.9 km2) |
• Land | 21.4 sq mi (55.5 km2) |
• Water | 0.1 sq mi (0.3 km2) |
Elevation | 2,198 ft (670 m) |
Population (2020) | |
• Total | 126 |
• Density | 6/sq mi (2.3/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 05201 |
Area code | 802 |
FIPS code | 50-63175[1] |
GNIS feature ID | 1462202[2] |
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